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帮忙写一个C语言程序 编一个求整数n的阶乘(n!)的...

#include int main() { int num; printf("input num"); scanf("%d",&num); int Sum=1; for(int i=1;i

//思路就是看下*i以后的数再除i能不能验算回来 #include int main(void){ int pre ; int i, n ; for (pre = n = i = 1; ; ++i) { n = pre*i ; //printf("%d! = %d\n", i, n) ; if (n/i != pre)//思路就是看下*i以后的数再除i能不能验算回来 brea...

#include int main() { int n,t,i; t=1; scanf("%d",&n); for(i=0;i

#includelong fac(unsigned n){if (n == 0 || n == 1){return 1;}else{return (n * fac(n - 1));}}int main(){unsigned ui;printf("输入计算的阶乘:");scanf("%u", &ui);printf("%u的阶乘为:%u\n", ui, fac(ui));return 0;} 注意: 0的阶乘是1...

/*求阶乘问题。输入一个正整数n,输出n! */#include //编译预处理命令 int factorial(int n); //函数声明 int main(int argc, char const *argv[]) //主函数 { int n; //变量定义scanf("%d", &n); //输入一个整数 if (n>=20){ printf("N is too...

#include int main() {int n,i,t=1,s=0; scanf("%d",&n); for(i=1;i

#include"stdio.h"int mul(int n);void main(){int i, n, num = 0;printf("输入待连续阶乘并求和的整数个数为:");scanf("%d", &n);for (i = 1; i

在手机上使用易历知食软件里的微C程序设计来编程,代码示例如下图(用递归方式): 运行结果:

#include//求阶乘int JC(int n){ if (n == 0 || n == 1) return 1; else return n*JC(n - 1);} int main(){ int n; printf("求1!+2!+...+n!的结果\n输入n的值: "); scanf("%d", &n); int sum = 0; for (int i = 1; i

#include double fun ( int n ) { double result = 1.0 ; if (n == 0) return 1.0 ; while( n >1 && n < 170 ) result *= n--; return result ; } main ( ) { int n ; printf("Input N:") ; scanf("%d", &n) ; printf("\n\n%d! =%lf\n\n", n, fu...

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